[tarheel1231]

Eyeballing the length of the launch, it looks to be in the 300 ft range.

2018-08-10.png (448.13KiB)Viewed 3421 times

The 530 teaspoons thing really confuses me. It's probably not capacity, as this should have relatively the same capacity as Icon which can take 1070 pph. It's too long to be the launch and too large to be the height.

Maybe it's the horsepower of the first launch?

[CarowindsFan]

Carowinds sort of confirmed that "25" was 2.5 seconds so 530 could certainly mean 53.0 mph. A 53 mph launch in 2.5 seconds makes sense.

[RiDeWaRrIoR]

More supports are here..

[uscbandfan]

And Google says you fall 1,000 ft in about 5.5 seconds, so given some liberties with what's considered height verses the fall, 2.5 seconds would "fit".

ok. not sure what Google told you about falling objects. Let's do a little math...

The force of gravity is 9.8 m/s(squared). That means that for every second you fall, your fall rate increases by a factor of 9.8 m/s. (32.15 feet per second) After the first second, you're falling at 32 feet per second... after the second second, you're falling at 64 feet per second... etc.

Fall time = square-root of ( 2 * height / 9.8 ).

Of course all of that doesn't take into account the factor of terminal velocity which is when your mass against air resistance evens out. (happens at roughly 120mph for a skydiver).

So, with a height of 500 feet (152.4 meters)
2*152.4 = 304.8
304.8 / 9.8 = 31.1020408...
squareroot of 31.1020408... = 5.57692...

... it will take 5.58 seconds to fall 500 feet.

I'll spare you the calculation but your speed when you hit the ground falling from 500 feet will be about 122 mph (not accounting for wind resistance of course).

incidentally, it will take 7.89 seconds to fall 1000 feet. (again not accounting for wind resistance.)

AND... a fall from 100 feet (30.5 meters) will take about 2.5 seconds. (again not accounting for wind resistance.)

Incidentally, terminal velocity for a 10000 pound roller coaster train is going to be a LOT higher than a man (around 300mph) so terminal velocity wouldn't really factor in for something that massive this close to the ground.

[uscbandfan]

And Google says you fall 1,000 ft in about 5.5 seconds, so given some liberties with what's considered height verses the fall, 2.5 seconds would "fit".

ok. not sure what Google told you about falling objects. Let's do a little math...

The force of gravity is 9.8 m/s(squared). That means that for every second you fall, your fall rate increases by a factor of 9.8 m/s. (32.15 feet per second) After the first second, you're falling at 32 feet per second... after the second second, you're falling at 64 feet per second... etc.

Fall time = square-root of ( 2 * height / 9.8 ).

Of course all of that doesn't take into account the factor of terminal velocity which is when your mass against air resistance evens out. (happens at roughly 120mph for a skydiver).

So, with a height of 500 feet (152.4 meters)
2*152.4 = 304.8
304.8 / 9.8 = 31.1020408...
squareroot of 31.1020408... = 5.57692...

... it will take 5.58 seconds to fall 500 feet.

I'll spare you the calculation but your speed when you hit the ground falling from 500 feet will be about 122 mph (not accounting for wind resistance of course).

incidentally, it will take 7.89 seconds to fall 1000 feet. (again not accounting for wind resistance and starting from a falling speed of ZERO.)

AND... a fall from 100 feet (30.5 meters) will take about 2.5 seconds. (again not accounting for wind resistance.)

Incidentally, terminal velocity for a 10000 pound roller coaster train is going to be a LOT higher than a man (around 300mph) so terminal velocity wouldn't really factor in for something that massive this close to the ground.

[hikernut79]

Carowinds sort of confirmed that "25" was 2.5 seconds so 530 could certainly mean 53.0 mph. A 53 mph launch in 2.5 seconds makes sense.

This is the most plausible explanation it seems to me.

As for "stir" the ingredients around in the pot, I think that could simply mean the layout of the coaster and not anything super specific. In other words, after the launch the fun begins with twists, turns and inversions which would be "stirring" the ingredients.

[CarowindsFan]

WolframAlpha is a good place to find this type of info and it agrees with those calculations: http://www.wolframalpha.com/input/?i=how+long+to+fall+500+feet

[Glitch99]

And Google says you fall 1,000 ft in about 5.5 seconds, so given some liberties with what's considered height verses the fall, 2.5 seconds would "fit".

ok. not sure what Google told you about falling objects. Let's do a little math...

The force of gravity is 9.8 m/s(squared). That means that for every second you fall, your fall rate increases by a factor of 9.8 m/s. (32.15 feet per second) After the first second, you're falling at 32 feet per second... after the second second, you're falling at 64 feet per second... etc.

Fall time = square-root of ( 2 * height / 9.8 ).

Of course all of that doesn't take into account the factor of terminal velocity which is when your mass against air resistance evens out. (happens at roughly 120mph for a skydiver).

So, with a height of 500 feet (152.4 meters)
2*152.4 = 304.8
304.8 / 9.8 = 31.1020408...
squareroot of 31.1020408... = 5.57692...

... it will take 5.58 seconds to fall 500 feet.

I'll spare you the calculation but your speed when you hit the ground falling from 500 feet will be about 122 mph (not accounting for wind resistance of course).

incidentally, it will take 7.89 seconds to fall 1000 feet. (again not accounting for wind resistance.)

AND... a fall from 100 feet (30.5 meters) will take about 2.5 seconds. (again not accounting for wind resistance.)

Incidentally, terminal velocity for a 10000 pound roller coaster train is going to be a LOT higher than a man (around 300mph) so terminal velocity wouldn't really factor in for something that massive this close to the ground.

For that matter, there will be different results between the front and back of the train - the back begins accelerating before the decent, thus starts the decent at a higher initial velocity. Add in track resitence, dispersement of the riders, where exactly the decent is considered to begin and end, and other variables, and there will never be a firm actual answer of how long it will take from top to bottom. But if you are just falling through the sky, on average you go 1,000ft every 5.5 seconds - which again, is just simple falling, not adjusting for speeding up at the start and slowing down at the end.

This is an informative tangent. But to be clear, I'm not trying to argue the validity of my speculation. There's virtually zero chance it is correct, but in theory it fits.

[Jrlooney88]

Eyeballing the length of the launch, it looks to be in the 300 ft range.

2018-08-10.png

The 530 teaspoons thing really confuses me. It's probably not capacity, as this should have relatively the same capacity as Icon which can take 1070 pph. It's too long to be the launch and too large to be the height.

Maybe it's the horsepower of the first launch?

I think it may be the combined launch track length, each launch could be 265 ft, or one slightly longer than the other, like 300 and 230. I look at the ingredients like a normal cook book, 3255 feet of track, 530 feet of launch track, 2 launches, then the recipe.

[uscbandfan]

530 could be the capacity per hour. At least that seems logical. So does the combined length of launch track.

But if you are just falling through the sky, on average you go 1,000ft every 5.5 seconds - which again, is just simple falling, not adjusting for speeding up at the start and slowing down at the end.

True. You are just quoting terminal velocity of a man which is approximately 120mph. 120 mph is about 5.6 seconds to travel 1000 feet. But you have to start from a downward velocity of zero at the crest of a hill.

A 10000 train's terminal velocity is over 300 mph so wind resistance isn't really a factor so terminal velocity doesn't apply. Of course, resistance of the track and the fact that the train would most probably NOT be traveling straight down would also be factors.

It also depends on how fast the track goes from level to downward and at what angle and how fast it levels back out at the bottom not to mention how fast the train is traveling on the track itself at the top which will accentuate the speed as it starts down, etc. etc.

I will say this, a fall of a coaster train straight down from 325 feet (99 meters) would be 4.5 seconds starting from a fall speed of zero and the speed at which it would hit the ground would be 98 mph. Fury 325 takes about 5 seconds for the center of the train to travel from the top of the hill to the bottom. So, the angle of decent and speed of the train looks to almost balance each other out at least in the case of Fury.... losing just over a half-second and 3 mph in the drop.

[tarheel1231]

I can’t see it being the capacity. Icon is a similar coaster in size that also has 3 trains with 16 riders, and it carries 1070 pph.

[Glitch99]

True. You are just quoting terminal velocity of a man which is approximately 120mph. 120 mph is about 5.6 seconds to travel 1000 feet. But you have to start from a downward velocity of zero at the crest of a hill.

How much complex math would you expect public relations teasers to use?

Besides, no roller coaster starts with a downward velocity of zero (ok, the flying cobra does). It has an unspecified forward velocity which is redirected downward by the track, giving it a running start into the descent. A coaster travelling at 50mph as it crests the hill will reach the bottom a lot quicker than a stopped coaster that just releases it's brakes.

[Carowinds Sully]

More supports are here..

Any pictures?

[Jrlooney88]

Found an interesting document of why the name Centurion possibly wasn't used, it looks like the USPTO suspended the trademark application in Feb. 2014, and Cedar Fair didn't receive the Notice of Publication until Oct. 2015

http://tsdr.uspto.gov/documentviewer?ca ... =22&page=1

http://tsdr.uspto.gov/#caseNumber=86094 ... atusSearch

[RiDeWaRrIoR]

They have poured concreter for the center of (possibly) the flyers! I can put a picture later or they are on my page!